typflu
C TYPFLU SOURCE CHAT 05/01/13 03:57:44 5004 C TYPFLU SOURCE AMAND 00/03/27 IMPLICIT INTEGER(I-N) IMPLICIT REAL*8(A-H,O-Z) DIMENSION CODU(9,9),CODL(8,8),COD(8) C SEGMENT BETJEF & TCON,DPSTF1,DPSTF2,TETA,PDT,TP00 INTEGER ICT,ICC,IMOD,IVIS,ITER, & ISIM,IBB,IGAU,IZON ENDSEGMENT SEGMENT BETFLU REAL*8 DATCOU,DATCUR,DATSEC,E28,PGTZO,PGDUR,TAU1,TAU2, & TP0,TZER INTEGER ITYPE,IMD,NBRC,NCOE,NTZERO,NTPS,IFOR ENDSEGMENT C C C VALEURS MAX DES PAS DE TEMPS C------------------------------ MC = NBRC+1 NTPS = 199 NTZERO = 199 NCOE = 8 NC = NCOE+1 C NTZERO1 = NTZERO+1 C NTPS1 = NTPS+1 TZER = 1.D0 PGTZO = 1.05 PGDUR = 1.05 C C C DEFINITION DES COEF DE RELAX DES COURBES DE MODULES DE RAIDEUR C IF(IFOR.EQ.1) THEN TAU1 = 2. TAU2 = 20. C---------------------------- DO 7 I=1,NCOE IF(I.EQ.1)THEN COD(I)=1. ELSE IF(I.EQ.2)THEN COD(I)=0.1 ELSE IF(I.EQ.3)THEN COD(I)=0.01 ELSE IF(I.EQ.4)THEN COD(I)=0.001 ELSE IF(I.EQ.5)THEN COD(I)=0.0001 ELSE IF(I.EQ.6)THEN COD(I)=0.00001 ELSE IF(I.EQ.7)THEN COD(I)=0.000001 ELSE IF(I.EQ.8)THEN COD(I)=0.0000001 ENDIF 7 CONTINUE C IF (CODU(1,1).EQ.0.D0.AND.CODU(9,9).EQ.0.D0) THEN ENDIF C C----------------------------- ELSE IF(IFOR.EQ.2) THEN C----------------------------- C TAU1 = 0.02 TAU2 = 2.00 DO 8 I = 1,NCOE IF(I.EQ.1)THEN COD(I) = 1. ELSE IF(I.EQ.2)THEN COD(I) = 0.1 ELSE IF(I.EQ.3)THEN COD(I) = 0.01 ELSE IF(I.EQ.4)THEN COD(I) = 0.001 ELSE IF(I.EQ.5)THEN COD(I) = 0.0001 ELSE IF(I.EQ.6)THEN COD(I) = 0.00001 ELSE IF(I.EQ.7)THEN COD(I) = 0.000001 ELSE IF(I.EQ.8)THEN COD(I) = 0.0000001 ENDIF 8 CONTINUE C IF (CODL(1,1).EQ.0.D0.AND.CODL(8,8).EQ.0.D0) THEN ENDIF C C----------------------------- ENDIF C----------------------------- RETURN END
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