flud
C FLUD SOURCE CB215821 16/04/21 21:16:54 8920 $ AN,BN,CN,NFLU,NDI) C C_______________________________________________________________________ C C SOUS PROGRAMME QUI CALCUL LES MATRICES DE DEFORMATION C DE FLUAGE PROPRE C D APRES LE MODELE DE KELVIN C_______________________________________________________________________ C IMPLICIT INTEGER(I-N) IMPLICIT REAL*8(A-H,O-Z) DIMENSION VARF(NVARI),CMAT(NMAT),EPSFLU(6) DIMENSION AN(*),BN(NDI,*),CN(NDI,*) C C C RECUPERATION DES VALEURS DES PARAMETRES MATERIAU C RRDV = CMAT(8 + (2 * NFLU) ) TDT = CMAT(NMAT) TDEV = CMAT(9 + (2 * NFLU)) TDEXP = EXP(-TDT/TDEV) XNU = CMAT(24) C C RECUPERATION DES VARIABLES INTERNES INITIALES C C REMPLISSAGE DES VECTEURS DE DEFORMATION DE FLUAGE C EPSFLU(1) = VARF(3 + (6 * NFLU) ) EPSFLU(2) = VARF(4 + (6 * NFLU) ) EPSFLU(3) = VARF(5 + (6 * NFLU) ) EPSFLU(4) = VARF(6 + (6 * NFLU) ) EPSFLU(5) = VARF(7 + (6 * NFLU) ) EPSFLU(6) = VARF(8 + (6 * NFLU) ) C C C CONSTRUCTION DE LA MATRICE C ADR = TDEXP - 1.D0 BDR = 1.D0/RRDV*( TDEXP*(-(2*TDEV/TDT+1.D0) + TDEV/TDT) $ + (2.D0*(TDEV-TDT)/TDT+1.D0) - (TDEV-TDT)/TDT ) CDR = 1.D0/(TDT*RRDV)*( TDEV*TDEXP - (TDEV - TDT) ) C DO 10 I=1,NSTRS AN(I) = ADR * EPSFLU(I) 10 CONTINUE C IF(IFOUR.EQ.-2) THEN C C - CONTRAINTES PLANES C BN(1,1)=1.D0 BN(1,2)=-XNU BN(2,1)=BN(1,2) BN(2,2)=BN(1,1) BN(3,3)=1.D0+XNU ELSE IF((IFOUR.EQ.-1).OR.(IFOUR.EQ.0)) THEN C C - DEFORMATION PLANE OU AXISYMETRIQUE C BN(1,1)=1.D0 BN(1,2)=-XNU BN(1,3)=BN(1,2) BN(2,1)=BN(1,2) BN(2,2)=BN(1,1) BN(2,3)=BN(1,2) BN(3,1)=BN(1,2) BN(3,2)=BN(1,2) BN(3,3)=BN(1,1) BN(4,4)=1.D0+XNU ELSE C C - CALCUL TRIDIMENSIONEL C BN(1,1)=1.D0 BN(1,2)=-XNU BN(1,3)=BN(1,2) BN(2,1)=BN(1,2) BN(2,2)=BN(1,1) BN(2,3)=BN(1,2) BN(3,1)=BN(1,2) BN(3,2)=BN(1,2) BN(3,3)=BN(1,1) BN(4,4)=1.D0+XNU BN(5,5)=BN(4,4) BN(6,6)=BN(4,4) ENDIF C DO 20 I=1,NSTRS DO 20 J=1,NSTRS CN(I,J) = CDR * BN(I,J) BN(I,J) = BDR * BN(I,J) 20 CONTINUE C END
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