elnlin
C ELNLIN SOURCE AM 11/05/26 21:15:22 6982 & delta_prec, Ftr, delta,deltamax) IMPLICIT INTEGER(I-N) IMPLICIT REAL*8(A-H,O-Z) * DIMENSION Res(3), AA(3,3),AA1(3,3),DVM(3) * a=da(8) b=da(9) c=da(10) d=da(11) e=da(12) f=da(13) a9=da(15) * A1=2.5 epsilon2=1E-12 C Calcul de la limite élastique en décollement. uelu=sqrt(uel(3)**2+uel(5)**2) XMKelu=1/sqrt(2.)*sqrt(XMKel(3,3)**2+XMKel(5,5)**2) * if (a9.eq.1) then q_1=4. q_2=1. else if (a9.eq.2) then q_1=4. q_2=1. else q_1=6. q_2=2. endif endif * * if (fe.le.0) then delta=delta_prec else * deltamax=1 * & +q_2*(delta_prec*deltamax)))/q_1-forceu gg1=-(((delta_prec/1.)/(1-(delta_prec/1.)) & +LOG(1.-(delta_prec/1.))) & +(1.-(delta_prec/1.))*(forceu-XMKelu*uelu) Res(1)=-ff1 Res(2)=-gg1 Res(3)=-Xhh1 XNorm_Res=SQRT(Res(1)**2.+Res(2)**2.+Res(3)**2.) do while (XNorm_Res.gt.epsilon2) dff1dM=-1. dgg1dV=(((delta_prec/1)/(1.-(delta_prec/1)) & /(2*q_1*XMKelu) & -(((delta_prec/1)/(1.-(delta_prec/1)) & +LOG(1.-(delta_prec/1))) dgg1dM=0 dhh1dM=1.-(delta_prec/1) AA(1,1)=dff1dV AA(1,2)=dff1dM AA(1,3)=dff1ddelta AA(2,1)=dgg1dV AA(2,2)=dgg1dM AA(2,3)=dgg1ddelta AA(3,1)=dhh1dV AA(3,2)=dhh1dM AA(3,3)=dhh1ddelta forceu=forceu+DVM(2) delta_prec=delta_prec+DVM(3) * & +q_2*(delta_prec*deltamax)))/q_1-forceu gg1=-(((delta_prec/1.)/(1.-(delta_prec/1.)) & +LOG(1.-(delta_prec/1.))) & +(1.-(delta_prec/1.))*(forceu-XMKelu*uelu) Res(1)=-ff1 Res(2)=-gg1 Res(3)=-Xhh1 XNorm_Res=SQRT(Res(1)**2.+Res(2)**2.+Res(3)**2.) enddo uelu1=sqrt(uel(3)**2+uel(5)**2) DO I=1,5 ENDDO delta=delta_prec endif return end
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